36x^2+24x-10=0

Solution for 36x^2+24x-10=0 equation:

36x^2+24x-10=0

a = 36; b = 24; c = -10;
Δ = b2-4ac
Δ = 242-4·36·(-10)
Δ = 2016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2016}=\sqrt{144*14}=\sqrt{144}*\sqrt{14}=12\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-12\sqrt{14}}{2*36}=\frac{-24-12\sqrt{14}}{72}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+12\sqrt{14}}{2*36}=\frac{-24+12\sqrt{14}}{72}
$